对于$x_{k+1} = g(x_k)$，$g$是不动点为$f(x)=0$的解函数

#include<iostream>
#include<string>
#include<cmath>
#define N 50 //最大迭达次数
using namespace std;
double f(double x) //目标函数
{
      return 1 + 0.5 * sin(x);
}

void work(double x0)
{
    double x = x0;
    for (int i = 1; i <= N; i++)
        x = f(x);
    cout << x << endl;
    return;
}

int main()
{
    double x0;
    cin >> x0;
    work(x0);
    return 0;

}